X^2+20x-11250=0

Solution for X^2+20x-11250=0 equation:

X^2+20X-11250=0

a = 1; b = 20; c = -11250;
Δ = b2-4ac
Δ = 202-4·1·(-11250)
Δ = 45400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{45400}=\sqrt{100*454}=\sqrt{100}*\sqrt{454}=10\sqrt{454}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-10\sqrt{454}}{2*1}=\frac{-20-10\sqrt{454}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+10\sqrt{454}}{2*1}=\frac{-20+10\sqrt{454}}{2}
$